ccna interview questions and answers

Part - 9 CCNA Interview Questions and Answers

41 You are given the following address: 153.50.6.27/25. Determine the subnet mask, address class, subnet address, and broadcast address.

A. 255.255.255.128, B,153.50.6.0, 153.50.6.127

B. 255.255.255.128, C,153.50.6.0, 153.50.6.127

C. 255.255.255.128, C,153.50.6.127, 153.50.6.0

D. 255.255.255.224, C,153.50.6.0, 153.50.6.127

Ans A

42 You are given the following address: 128.16.32.13/30. Determine the subnet mask, address class, subnet address, and broadcast address.

A. 255.255.255.252, B,128.16.32.12, 128.16.32.15

B. 255.255.255.252, C,128.16.32.12, 128.16.32.15

C. 255.255.255.252, B,128.16.32.15, 128.16.32.12

D. 255.255.255.248, B,128.16.32.12, 128.16.32.15

Ans A

43 You are given the following address: 15.16.193.6/21. Determine the subnet mask, address class, subnet address, and broadcast address.

A. 255.255.248.0, A, 15.16.192.0, 15.16.199.255

B. 255.255.248.0, B, 15.16.192.0, 15.16.199.255

C. 255.255.248.0, A, 15.16.199.255, 14.15.192.0

D. 255.255.242.0, A, 15.16.192.0, 15.16.199.255

Ans A

44 You have an IP host address of 201.222.5.121 and a subnet mask of 255.255.255.248.
What is the broadcast address?

A. 201.222.5.127

B. 201.222.5.120

C. 201.222.5.121

D. 201.222.5.122

Ans A

The easiest way to calculate this is to subtract 255.255.255.248 (subnet mask) from 255.255.255.255, this equals 7. Convert the address 201.222.5.121 to binary--11001001 11011110 00000101 01111001. Convert the mask 255.255.255.248 to binary--11111111 11111111 11111111 11111000. AND them together to get: 11001001 11011110 00000101 01111000 or 201.222.5.120. 201.222.5.120 is the subnet address, add 7 to this address for 201.222.5.127 or the broadcast address. 201.222.5.121 through 201.222.5.126 are the valid host addresses.

45 Given the address 172.16.2.120 and the subnet mask of 255.255.255.0. How many hosts are available?

A. 254

B. 510

C. 126

D. 16,372

Ans A

172.16.2 120 is a standard Class B address with a subnet mask that allows 254 hosts. You are a network administrator and have been assigned the IP address of 201.222.5.0. You need to have 20 subnets with 5 hosts per subnet. The subnet mask is 255.255.255.248.